4x^2-132=-2x

Solution for 4x^2-132=-2x equation:

4x^2-132=-2x

We move all terms to the left:

4x^2-132-(-2x)=0

We get rid of parentheses

4x^2+2x-132=0

a = 4; b = 2; c = -132;
Δ = b2-4ac
Δ = 22-4·4·(-132)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-46}{2*4}=\frac{-48}{8}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+46}{2*4}=\frac{44}{8}
=5+1/2
$